GMAT Practice Question of the Day

This problem requires us to find the greatest number of people who could have contributed to the $303 collected at the church service. In order to do so, we must assume that each person gave the minimum amount possible given the terms of the problem. In this case, we would therefore divide the total amount collected, $303, by the minimum contribution, $2.50, to find the maximum number of participants. . Now 121 x $2.50 = $302.50. Since each person must contribute at least $2.50, an additional person cannot contribute the remaining $0.50. The remaining $0.50 must be contributed by one or more of the 121 people. So choice (C), 121, is correct.

Alternatively, to avoid the long division, we could think like this: paying the minimum amount means $2.50 per person, or $5 for two people. $5 times 60 pairs of people is $300, so 120 people paying $2.50 each comes to $300. Now we're just $3 short; that $3 will be paid by one extra person, since nobody can pay just $0.50.

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